array
(
[0] => array
(
[0] => https://adc.cn/public/image/1.jpg
[1] => http://www.adc.com/
)
[1] => array
(
[0] => https://adc.cn/public/image/2.jpg
[1] => http://www.adc.com/
)
[2] => array
(
[0] => https://adc.cn/public/image/3.jpg
[1] => http://www.adc.com/
)
)
如何json输出
{“link”: {
“rel”: “https://adc.cn/public/image/3.jpg”,
“href”: ” http://www.adc.com/”,
}}
回复讨论(解决方案)
只要最后一个？
$a = array(
array(
‘https://adc.cn/public/image/1.jpg’,
‘http://www.adc.com/’,
),
array(
‘https://adc.cn/public/image/2.jpg’,
‘http://www.adc.com/’,
),
array(
‘https://adc.cn/public/image/3.jpg’,
‘http://www.adc.com/’,
),
);
$r = array(‘link’ => array_combine(array(‘rel’, ‘href’), array_pop($a)));
echo json_encode($r, json_unescaped_slashes);
{“link”:{“rel”:”https://adc.cn/public/image/3.jpg”,”href”:”http://www.adc.com/”}}