python实现批量下载文件
#!/usr/bin/env python
# -*- coding:utf-8 -*-
from gevent import monkey
monkey.patch_all()
from gevent.pool import pool
import requests
import sys
import os
def download(url):
chrome = ‘mozilla/5.0 (x11; linux i86_64) applewebkit/537.36 ‘ +
‘(khtml, like gecko) chrome/41.0.2272.101 safari/537.36’
headers = {‘user-agent’: chrome}
filename = url.split(‘/’)[-1].strip()
r = requests.get(url.strip(), headers=headers, stream=true)
with open(filename, ‘wb’) as f:
for chunk in r.iter_content(chunk_size=1024):
if chunk:
f.write(chunk)
f.flush()
print filename,”is ok”
def removeline(key, filename):
os.system(‘sed -i /%s/d %s’ % (key, filename))
if __name__ ==”__main__”:
if len(sys.argv) == 2:
filename = sys.argv[1]
f = open(filename,”r”)
p = pool(4)
for line in f.readlines():
if line:
p.spawn(download, line.strip())
key = line.split(‘/’)[-1].strip()
removeline(key, filename)
f.close()
p.join()
else:
print ‘usage: python %s urls.txt’ % sys.argv[0]
其他网友的方法：
from os.path import basename
from urlparse import urlsplit
def url2name(url):
return basename(urlsplit(url)[2])
def download(url, localfilename = none):
localname = url2name(url)
req = urllib2.request(url)
r = urllib2.urlopen(req)
if r.info().has_key(‘content-disposition’):
# if the response has content-disposition, we take file name from it
localname = r.info()[‘content-disposition’].split(‘filename=’)[1]
if localname[0] == ‘”‘ or localname[0] == “‘”:
localname = localname[1:-1]
elif r.url != url:
# if we were redirected, the real file name we take from the final url
localname = url2name(r.url)
if localfilename:
# we can force to save the file as specified name
localname = localfilename
f = open(localname, ‘wb’)
f.write(r.read())
f.close()
download(r’你要下载的python文件的url地址’)
以上便是本文给大家分享的全部内容了，小伙伴们可以测试下哪种方法效率更高呢。