a=[1,2,3,4,5,6]b=[‘a’,’b’,’c’,’d’,’e’]实现合并后[1,’a’,2,’b’,3,’c’……]这种类型回复内容：
from compiler.ast import flatten
a = [1, 2, 3, 4, 5, 6]
b = [‘a’, ‘b’, ‘c’, ‘d’, ‘e’]
c = flatten(zip(a, b))
print c
[1, ‘a’, 2, ‘b’, 3, ‘c’, 4, ‘d’, 5, ‘e’]
import itertools
list(itertools.chain.from_iterable(zip(a,b)))
办法有多种，其中一种，解题思路是模拟队列，由黄哥所写。
a = [1, 2, 3, 4, 5, 6]
b = [‘a’, ‘b’, ‘c’, ‘d’, ‘e’]
c = []
map(lambda x, y: c.extend([x,y]) if none not in [x,y] else none, a, b)
print c
[1, ‘a’, 2, ‘b’, 3, ‘c’, 4, ‘d’, 5, ‘e’]
有规律的交叉合并可以通过for循环来实现的吧